Effects of Indoor Plants on Air Pollution

Effects of Indoor Plants on Air Pollution Are indoor plants adapted to get rid formaldehyde, Sipin, Elly Lorreta one of the noxious wastes commonly found at home 002348-019 nowadays? 1.0 Introduction I did further research and found out that indoor air pollution phenomenon has urged the NASA (National Aeronautics and Space Administration) scientists to study the functions of plants to provide clean indoor air. NASA has become the pioneer towards this research and recently has been widened by many other associations like the Wolverton Environmental Services, Inc. endorsed by the Plants for Clean Air Council in Mitchellville, Maryland[1]. Research done by NASA has found out that there are certain plants that have the function to purify the air in a building[2]. They detoxify the existing toxins and pollutants which originate from the things used in daily activities nowadays; fabrics, detergents and also furniture. These pollutants can be classified into three common indoor pollutants according to the list of indoor contaminant that are currently present. There are benzene, formaldehyde and trichloroethylene. (TCE)[3] Plants use the concept of transpiration to work onto this problem[4]. As the vaporized chemical enters the stomatal opening on the leaves of the indoor plants, they are either broken down directly or be sent downwards; down to the root system of the plants.[5] The presence of colonies of microbes at the root system breaks down various kinds of unhealthy compounds; in this case the indoor pollutants, and absorbs them as their source of food[6]. As for the mechanism of transpiration to remove the pollutant, water vapour that is liberated by the leaves of the plants will mix with the air in the atmosphere. Convection of air leads to the movement of the atmospheric air that is contaminated with the vaporized chemical downwards to the base of the plants. I chose 6 types of plants to be experimented by one fixed type of pollutant; formaldehyde. It is normally used in the production of grocery bags, facial tissues, waxed paper, waxed paper[7] and produced by tobacco products, gas cookers and open fireplaces.[8] In the experiment, this chemical is predicted to be absorbed by each plant. Plant that absorbs the chemical the most would be the efficient plant to be included in places mentioned before. 2.0 Aim To study the effect of plants transpiration towards the acidity and mass of formaldehyde in a transparent chamber. 3.0 Planning and method development Firstly, a chamber must be set up to place plants chosen. A pot of selected plant is placed into each chamber. 6 types of plants were chosen, therefore 6 chambers must be created. To make sure that air, sunlight and water could be continuously supplied, I decided that the chamber must be transparent, and there are holes to let air enters. The material that I chose is transparent plastic so that holes can be poked, the wall of the chambers can be flipped to water the plants everyday and plants get sufficient sunlight. I selected formaldehyde as the pollutant to the plants. In each of the chamber, I included formalin of the same amount in a beaker and let it evaporate in the chamber. As formalin CH2O, is a reducing agent[9], therefore it has the ability to release its hydrogen.[10] The more hydrogen ions present in it, the greater the strength of the acid. When evaporation of formalin happens continuously, there will be less in quantity of hydrogen atoms in the aqueous solution. Thus, the acidity of formaldehyde could decrease through evaporation; pH of the formalin increases. So, the pH of the formalin is ought to be checked for every interval of two days. Because concept of evaporation is used, it is for sure the volume of the formalin will reduce. The most effective method to measure this is by getting the mass decrease. I took the reading of the mass of formalin for every interval of two days. I decided to take note on the external condition of all the plants so that analysis on that can be don e to find its relativity with formalin. 4.0 Hypothesis My prediction is that indoor plants have the ability to get rid of formaldehyde, one of the noxious wastes commonly found at home nowadays by absorbing the chemicals through their microscopic openings perforated on their leaves; the stomata[11]. As the chemical evaporates, the molecules of the chemical are absorbed by the plants by gaining entrance through the stomata. These plants transport the absorbed chemical to their root system along the xylem of the plants to be broken down by the microbes present at the roots.[12] As formalin acts as a reducing agent, release of hydrogen could occur. Through evaporation of formalin, there will be less hydrogen atoms could remain in the aqueous solution. Thus, it is possible for the decrease in mass and increase in the pH of the formalin to occur when indoor plants are available. 5.0 Methodology 5.1 Variables a) Independent: * Types of plants chosen to be experimented There are variety types of plants chosen in order to know whether the hypothesis could be accepted. They are Boston fern (Nephrolepis exaltata â€Å"Bostoniensis†), Janet Craig(Dracaena deremensis), Florists mum(Chrysanthemum morifolium), Kimberly queen fern (Nephrolepis obliterata), Snake plant or mother-in-laws tongue (Sansevieria trifasciata Laurentii), Himalayan Balsam (Impatiens glandulifera) altogether. Himalayan Balsam (Impatiens glandulifera) acts as the control of the experiment to show its less in efficiency to absorb the toxin. Some plants have no ability to absorb the chosen toxin as good as in some indoor plants. b) Dependent: * The rate of absorption of formaldehyde The rate of absorption of formaldehyde is taken as the decrease in mass of formalin over time. This is documented for every interval of two days. Other than that, the acidity of formaldehyde in each chamber is also noted. This is done by using pH paper and pH meter to indicate the change in pH. The pH of the formalin in the chamber is recorded to see the pattern of change in acidity. c) Fixed: * The type of toxin chosen; formaldehyde Liquid formalin is selected to be one of the fixed variables in this experiment so that the analysis of the change in acidity can be done easily. More than one type of pollutant will promote confusion while conducting the experiment as the characteristic of one pollutant differ from one to another. Formalin is the aqueous state of the chemical formaldehyde and the concentration of the liquid formalin is 100%. I made the volume and the concentration of liquid formalin the same in every small beaker included in every transparent chamber. It is important to do so because the pH of the chemical and its mass are to be checked every 2 days throughout the duration of the experiment. The initial pH of the chemical is 3.510 while the initial volume of the chemical is 10  ± 0.5 ml making its mass to be 10.19  ± 0.01 g * The estimated size of the plants chosen The chosen plants are of the same size. There is no specific measurement for the plants sizes so therefore, the size is depending on the experimenters justification by fixing the number of leaves present in every plant chosen. This is due to the mechanism of the absorption of the chemical formalin happens through the microscopic opening present on the leaves; the stomata. It is therefore can be predicted that more tiny opening present on the leaves, the more effective would the rate of absorption be. I decided that the total number of leaves is approximately 15-20 leaves depending on the how broad the surface of the leaves is. * The size of the pyramidal transparent chamber The size of the pyramidal transparent chamber is to be made constant by using the same size and number of transparent plastic bags. The size of the plastic bags is 23cm x 38cm and they are cut into same shapes to fit it with the skeleton of the chamber. The base of the chamber is triangular in shape and constant with the area of  ½ (50cm x 50cm). 5.2 Materials MATERIALS QUANTITY JUSTIFICATION Formalin 120ml Formalin acts as the toxin in the experiment. Tap Water 5 litres This is used to water the plants everyday for 2 weeks duration. 5.3 Apparatus APPARATUS QUANTITY JUSTIFICATION Boston fern (N. exaltata) 1 pot These are the plants chosen to determine their effectiveness to absorb the formalin. Janet Craig (D. deremensis) 1 pot Florists mum (C. morifolium) 1 pot Kimberly queen fern (N. obliterata) 1 pot Snake plant (S. trifasciata) 1 pot Himalayan Balsam (I. glandulifera) 1 pot pH paper 1 box To check the acidity of formalin every 2 days. pH meter 1 To determine the pH of the formalin every 2 days. Disposable plastic cups 24 To be the base of the pyramidal transparent chamber. Plastic and bamboo chopsticks 54 To be the poles of the pyramidal transparent chamber. Electronic balance 1 To measure the decrease in mass of the liquid formalin for every 2 days. 50ml beaker 6 To place the liquid formalin in each chamber. 50ml measuring cylinder 1 To measure the amount of formalin in each 50ml beaker. Transparent plastics for packaging (23cm x 38cm) 1 pack To become the cover of the chamber. 5.4 Methodology to prepare a chamber for the plant A chamber has to be invented to place the chosen plants, considering the needs of those plants to get sufficient sunlight, air and water. I chose transparent plastics and attach them together to create a pyramidal transparent chamber. Holes were also poked to allow air move into the chamber. I included nine chopsticks to be the poles of chamber. A pole comprised of 3 combined chopsticks. To increase its stability, I poked a hole onto the bases of three disposable plastic cups and inserted the chopsticks into the holes. 5.5 Methodology to determine the change in acidity of formaldehyde After the chamber was set up, I prepared the solution of the toxin chosen; formalin.in a 50ml beaker. 10  ± 0.5 ml of the chemical in each beaker was measured using 50ml measuring cylinder. 6 transparent chambers were set up to place 6 types of plants which were the Boston fern (N. exaltata), Janet Craig (D. deremensis), Florists mum (C. morifolium), Kimberly queen fern (N. obliterata), Snake plant (S. trifasciata), and Himalayan Balsam (I. glandulifera). All the 6 chambers contained different pots of plants and 10ml of formalin in a 50ml beaker. At intervals of 2 days, the mass of the formalin was recorded. The procedure to get the mass of formalin in each chamber was as follows; * Take the reading of the mass of 50ml beaker before filling in the formalin by using electronic balance. Repeat the steps 3 times in order to get the average reading. * Weigh the 50ml beaker containing formalin by using electronic balance. Repeat the procedure 3 times in order to get the average reading. The reading of the mass of the formalin + 50ml beaker at intervals of 2 days was recorded. The mass of the formalin was determined by subtracting the average value of the mass of formalin + 50ml beaker with the average mass of the 50ml beaker. The pH was again checked by using pH paper and also pH meter for 2 weeks. The change in colour of the pH paper and the reading of the pH meter were noted and documented. Each of the plants in the chamber was watered once a day using tap water. The amount of tap water must was 20ml per watering and watering time was at 10.30 a.m and 4.00 p.m. every day. Condition for each of the plants was observed for interval time of 2 days. All of results were recorded in a table. 5.5.1 Precaution 1. Beware while handling formalin because it is a dangerous chemical. Since a high concentration of formaldehyde will be used in the experiment, [13]it may cause burning sensation to the eyes, nose and lungs. Thus it could result in allergic reaction because of formalin. 2. Be cautious when building the pyramidal transparent chamber especially when dealing with the bamboo sticks. Avoid any sharp splinter of the bamboo stick from piercing into the skin. 6.0 Data collection TABLE 1: THE pH of FORMALIN IN EACH TRANSPARENT CHAMBER WITH DIFFERENT PLANTS IN 14 DAYS Transparent chamber containing plants Value of Ph of formalin in each transparent chamber according to number of days 2 days 4 days 6 days 8 days 10 days 12 days 14 days Boston fern (N. exaltata â€Å"Bostoniensis†) 3.510 3.550 3.570 4.020 4.130 4.260 4.310 Janet Craig (D. deremensis) 3.510 3.570 3.580 4.020 4.070 4.210 4.430 Florists mum (C. morifolium) 3.510 3.570 3.590 4.120 4.200 4.320 4.620 Kimberly queen fern (N. obliterate) 3.510 3.510 3.520 4.010 4.030 4.050 4.110 Snake plant (S. trifasciata Laurentii) 3.510 3.370 3.360 4.030 4.030 4.030 4.030 Himalayan Balsam (I. glandulifera) 3.510 3.370 3.370 3.350 3.350 3.350 3.350 Note: The pH of formalin in each beaker was checked at the same interval to ensure that none of the formalin being absorbed more by their respective plants. The time that they were checked was at a range of 4.00 p.m. until 4.45 p.m. 10 Are indoor plants adapted to get rid formaldehyde, Sipin, Elly Lorreta one of the noxious wastes commonly found at home 002348-019 nowadays? TABLE 2: MASS OF FORMALIN + 50ml BEAKER IN EACH CHAMBER CONTAINING DIFFERENT PLANTS IN 14 DAYS Transparent chamber containing plants Mass of formalin + 50ml beaker in each transparent chamber  ± 0.01g 2 days 4 days 6 days 1st 2nd 3rd 1st 2nd 3rd 1st 2nd 3rd Boston fern (N. exaltata) 46.950 46.960 46.960 46.530 46.540 46.550 46.230 46.220 46.220 Janet Craig (D. deremensis) 46.910 46.910 46.910 46.520 46.520 46.510 46.310 46.310 46.310 Florists mum (C. morifolium) 46.940 46.940 46.950 46.610 46.600 46.610 46.350 46.340 46.350 Kimberly queen fern (N. obliterata) 46.970 46.970 46.970 46.620 46.620 46.640 46.430 46.410 46.410 Snake plant (S. trifasciata) 46.920 46.910 46.910 46.620 46.630 46.610 46.420 46.410 46.430 Himalayan Balsam(I. glandulifera) 46.940 46.940 46.930 46.780 46.790 46.790 46.720 46.710 46.720 Note: The mass of the formalin was measured at intervals of 2 days and it was at a range of time from 4.00 p.m. until 4.45 p.m. 10 Are indoor plants adapted to get rid formaldehyde, Sipin, Elly Lorreta one of the noxious wastes commonly found at home 002348-019 nowadays? Transparent chamber containing plants Mass of formalin + 50ml beaker in each transparent chamber  ± 0.01g 8 days 10 days 12 days 14 days 1st 2nd 3rd 1st 2nd 3rd 1st 2nd 3rd 1st 2nd 3rd Boston fern (N. exaltata) 46.010 46.030 46.040 45.480 45.480 45.470 45.210 45.220 45.220 44.950 44.960 44.980 Janet Craig (D. deremensis) 45.520 45.530 45.530 45.030 45.030 45.020 44.960 44.960 44.920 44.580 44.590 44.580 Florists mum (C. morifolium) 45.550 45.550 45.560 45.220 45.210 45.220 44.940 44.940 44.950 44.130 44.130 44.140 Kimberly queen fern (N. obliterata) 45.500 45.510 45.510 45.320 45.350 45.350 44.980 44.980 44.990 44.220 44.230 44.230 Snake plant (S. trifasciata) 45.890 45.900 45.890 45.530 45.530 45.530 45.140 45.140 45.120 44.970 44.960 44.970 Himalayan Balsam(I. glandulifera) 46.680 46.680 46.680 46.340 46.340 46.320 46.290 46.290 47.300 46.250 46.240 46.250 10 Are indoor plants adapted to get rid formaldehyde, Sipin, Elly Lorreta one of the noxious wastes commonly found at home 002348-019 nowadays? Transparent chamber containing plants Change in colour of pH paper 2 days 4 days 6 days 8 days 10 days 12 days 14 days Boston fern (N. exaltata) Green leaves Green leaves Green leaves Green leaves Green leaves Green leaves Green leaves Janet Craig (D. deremensis) Green leaves Green leaves Green leaves Green leaves Green leaves Yellow leaves Brown Leaves Florists mum (C.morifolium) Green leaves Green leaves Green leaves Wilted flowers Wilted flowers Yellow leaves Yellow leaves K. queen fern (N. obliterata) Green leaves Green leaves Green leaves Green leaves Yellow leaves Yellow leaves Yellow leaves Snake plant (S. trifasciata) Green leaves Green leaves Green leaves Green leaves Green leaves Green leaves Green leaves H. Balsam (I. glandulifera) Green leaves Green leaves Yellow leaves Yellow leaves Yellow leaves Brown leaves Brown leaves TABLE 3: DAILY CONDITION OF PLANTS IN THE TRANSPARENT CHAMBERS IN 14 DAYS Note: Only Florists mum (C.morifolium) in this experiment has flowers. When the edges of the leaves becoming brown or yellow, it is indicated as having brown leaves or yellow leaves. The font in italic form indicates the adverse change onto the plants. 10 Are indoor plants adapted to get rid formaldehyde, Sipin, Elly Lorreta one of the noxious wastes commonly found at home 002348-019 nowadays? TABLE 4: CHANGE IN COLOUR OF pH PAPER WHEN pH OF FORMALIN FOR A DURATION OF TWO WEEKS Transparent chamber containing plants Change in colour of pH paper 2 days 4 days 6 days 8 days 10 days 12 days 14 days Boston fern (N. exaltata ) Light orange Light orange Light orange Light orange Light orange Light orange Light orange Janet Craig (D. deremensis) Light orange Light orange Light orange Light orange Light orange Light orange Light orange Florists mum (C. morifolium) Light orange Light orange Light orange Light orange Light orange Light orange Light orange K. queen fern (N. obliterata) Light orange Light orange Light orange Light orange Light orange Light orange Light orange Snake plant (S. trifasciata) Light orange Light orange Light orange Light orange Light orange Light orange Light orange H. Balsam (I. glandulifera) Light orange Light orange Light orange Light orange Light orange Light orange Light orange Note: The original colour of the pH paper is light yellow in colour 10 Are indoor plants adapted to get rid formaldehyde, Sipin, Elly Lorreta one of the noxious wastes commonly found at home 002348-019 nowadays? 7.0 Data processing 7.1 pH difference of formalin I discover that there are some changes in pH of the formalin in the transparent chamber. The following table shows the total difference in the final and the initial pH of the formalin in each transparent chamber. TABLE 5: DIFFERENCE IN pH OF FORMALIN IN EACH TRANSPARENT CHAMBER Transparent chamber containing plants Final pH Initial pH Difference in pH Boston fern (N. exaltata) 4.310 3.510 0.800 Janet Craig (D. deremensis) 4.430 3.510 0.920 Florists mum (C. morifolium) 4.620 3.510 1.110 Kimberly queen fern (N. obliterate) 4.110 3.510 0.600 Snake plant (S. trifasciata) 4.030 3.510 0.520 Himalayan Balsam (I. glandulifera) 3.350 3.510 0.160 Note: The method to calculate the pH of formalin in chamber containing Himalayan Balsam is inverted, since the pH value decreased so that negative value can be ignored. 7.2 Data for mean mass of formalin The following table shows the average mass of formalin + 50ml beaker for 14 days TABLE 6: AVERAGE MASS OF FORMALIN + 50ml BEAKER IN EACH CHAMBER CONTAINING DIFFERENT PLANTS IN 14 DAYS Transparent chamber containing plants Average mass of formalin+50ml beaker in each chamber  ± 0.01g Day 2 Day 4 Day 6 Day 8 Day 10 Day 12 Day 14 Boston fern (N. exaltata) 46.960 46.540 46.220 46.030 45.480 45.220 44.960 Janet Craig (D. deremensis) 46.910 46.520 46.310 45.530 45.030 44.950 44.580 Florists mum (C. morifolium) 46.940 46.610 46.350 45.550 45.220 44.540 44.130 K. queen fern (N. obliterate) 46.970 46.630 46.420 45.510 45.340 44.980 44.240 Snake plant (S. trifasciata) 46.910 46.620 46.420 45.890 45.330 45.130 44.970 H. Balsam (I. glandulifera 46.940 46.790 46.720 46.680 46.330 46.290 44.250 Note: The average masses were obtained by totaling up the three mass values in three trials, and divide it into three. 7.3 Graph for the decreasing mass of formalin In order to get a graph of decrease in mass of formalin from day 0 to day 14, the real mass of formalin is required. Therefore, the table of mass of formalin for a duration of 14 days is made as follows. The formulation to calculate the mass of formalin in each beaker would be; Mass of formalin= [(Average mass of formalin+50ml beaker)- Average mass of 50ml beaker] TABLE 7: MASS OF FORMALIN IN EVERY 50ml BEAKER CONTAINED IN TRANSPARENT CHAMBER WITH DIFFERENT TYPES OF PLANTS Transparent chamber containing plants Mass of formalin  ± 0.01g [(Average mass of formalin+50ml beaker) Average mass of 50ml beaker] Day 2 Day 4 Day 6 Day 8 Day 10 Day 12 Day 14 Boston fern (N. exaltata) 10.170 9.750 9.430 9.240 8.690 8.430 8.170 Janet Craig (D. deremensis) 10.120 9.730 9.520 8.740 8.240 8.160 7.790 Florists mum (C. morifolium) 10.150 9.820 9.560 8.760 8.430 8.150 7.340 K. queen fern (N. obliterate) 10.180 9.840 9.630 8.760 8.430 8.150 7.450 Snake plant (S. trifasciata) 10.120 9.830 9.630 9.100 8.540 8.340 8.180 H. Balsam (I. glandulifera 10.150 10.000 9.930 9.890 9.540 9.500 9.460 Note: The average mass of one 50ml beaker is 36.79  ± 0.1g. This value was used to calculate the mass above. The bar graph of decrease in mass of the formalin against number of days for each beaker containing formalin in every transparent chamber is as follows; graph 1: decrease in mass of the formalin against number of days for each beaker containing formalin in every transparent chamber Note: The graph shows quite obvious inclination of mass of formalin in all chambers except for the H. Balsam (I. glandulifera) 7.4 Mass and percentage of formalin absorbed The initial average mass of the 10ml formalin in the 50ml beaker is 46.980  ± 0.01g and the average mass of the 50ml beaker alone is 36.790  ± 0.01g making the mass of the 10.000  ± 0.1 ml formalin poured in to be 10.190  ± 0.01g. From the data, there is a decreasing pattern of the mass of the formalin in the 50ml beaker. The percentage of decrease in mass of the 10.000  ± 0.1 ml formalin in 14 days of time in respective transparent chamber of plants can be determined. Before that, the mass of formalin absorbed in all the 6 transparent chambers must be d up. Calculation is as follows; TABLE 8: MASS OF FORMALIN ABSORBED BY PLANTS IN EACH CHAMBER Name of plants in each chamber Mass of formalin absorbed [Initial mass (10.190)- Mass on the14th day]  ± 0.01g Boston fern (N. exaltata) 2.020 Janet Craig (D. deremensis) 2.400 Florists mum (C. morifolium) 2.850 Kimberly queen fern (N. obliterate) 2.740 Snake plant (S. trifasciata) 2.010 H. Balsam (I. glandulifera 0.730 Note: The mass of formalin absorbed by plants in each chamber is referring to the decrease in mass of formalin throughout the 12 days duration. It is possible to calculate the percentage of decrease in mass of formalin absorbed by using the formulation below. The table below shows the percentage in respective 50ml beaker of formalin in all 6 chambers; Percentage of decrease in = Mass of formalin absorbed x 100% mass of formalin Initial mass of formalin TABLE 9: PERCENTAGE DECREASE IN MASS OF FORMALIN IN THE 50ml BEAKER IN RESPECTIVE TRANSPARENT CHAMBER Transparent chamber containing plants Percentage of decrease in mass of formalin absorbed Percentage of decrease in mass of formalin (%) Boston fern (N. exaltata) 2.020/10.190 x 100 19.820 Janet Craig (D. deremensis) 2.400/10.190 x 100 23.550 Florists mum (C. morifolium) 2.850/10.190 x 100 27.970 Kimberly queen fern (N. obliterate) 2.740/10.190 x 100 26.890 Snake plant (S. trifasciata) 2.010/10.190 x 100 19.730 Himalayan Balsam (I. glandulifera) 0.730/10.190 x 100 7.160 Note: The comparison of decrease in mass of formalin in beaker is based on the initial mass of formalin in the beaker. The greater the percentage of decrease in masses of formalin, the better the quality of air in the chamber, the better formalin absorber would the plant be. The following diagram shows the ascending order of the quality of plant as formalin absorber. Himalayan Balsam (I. glandulifera) Snake plant (S. trifasciata) Boston fern (N. exaltata) Janet Craig (D. deremensis) Kimberly queen fern (N. obliterate) Florists mum (C. morifolium) 7.5 Calculation for mean, standard deviation and T-test TABLE 10 : TABLE OF MEAN AND STANDARD DEVIATION FOR EVERY PLANTS CHOSEN Mass  ± 0.01g Plants Boston fern (N. exaltata) Janet Craig (D. deremensis) Florists mum (C. morifolium) Kimberly queen fern (N. obliterata) Snake plant (S. trifasciata) Himalayan Balsam (I. glandulifera) 1st trial 2.000 2.330 2.810 2.000 1.950 0.690 2nd trial 2.000 2.320 2.810 2.740 1.950 0.700 3rd trial 1.980 2.330 2.810 2.740 1.940 0.680 Mean 1.993 2.327 2.810 2.493 1.947 0.690 Std. Dev 0.009 0.005 0.000 0.349 0.005 0.008 Note: The mean was determined by getting the difference of mass of formalin between 14th day with the 0 day; initial mass. The formulation to calculate t-test is as follows; t-value =_____difference in mean___ difference of standard error TABLE 11: TABLE OF T-VALUE FOR THE COMPARISON OF MASS DECREASE MEAN BETWEEN BOSTON FERN (N. exaltata) AND JANET CRAIG (D. deremensis) Mass  ± 0.01g Plants Boston fern (N. exaltata) Janet Craig (D. deremensis) Difference between Boston fern and Janet Craig 1 trial 2.000 2.330 0.330 2 trial 2.000 2.320 0.320 3 trial 1.980 2.330 0.340 Mean 1.993 2.327 0.330 Std. Dev 0.009 0.005 0.008 Std. Error 1.151 1.343 0.191 Degree of freedom 2.000 Critical value at 5% level 4.300 t-value 1.728 Null Hypothesis: There is no significance difference for decrease in mass between Boston fern (N. exaltata) and Janet Craig (D. deremensis) | t | = 1.728 Thus, null hypothesis is rejected. The mean difference is not significant TABLE 12: TABLE OF T-VALUE FOR THE COMPARISON OF MASS DECREASE MEAN BETWEEN BOSTON FERN (N. exaltata) AND FLORISTS MUM (C. morifolium) Null Hypothesis: There is no significance difference for decrease in mass between Boston fern (N. exaltata) and Florists mum (C. morifolium) Mass  ± 0.01g Plants Boston fern (N. exaltata) Florists mum (C. morifolium) Difference between Boston fern and Florists mum

Of Mice & Men: Forced Isolation Essay

Everyone in their lifetime desires the comfort of a friend, but will settle for the attentive ear of a stranger. In the novel, Of Mice and Men, Steinbeck shows how lonely people were during the 1930’s. He teaches a grim lesson about the nature of human existence, and how the characters in the story had to admit at one time or another to having a profound sense of loneliness and isolation. Although each character had their own secluded troubles, Curley’s wife, Crooks, and Candy, suffered the most from loneliness. Curley’s wife is the only female character in the story who is never given a proper, and is only mentioned in reference to her husband. The men on the farm refer to her as a â€Å"tramp†, a â€Å"tart†, and a â€Å"looloo†, and she represents the temptation of female sexuality in a male-dominated world. Steinbeck depicts Curley’s wife not as a villain, but rather as a victim. Like the ranch-hands, she is desperately lonely and has broken dreams of a better life. For example, she tells Lennie, â€Å"I get lonely. You can talk to people, but I can’t talk to nobody but Curley.† (95) This shows how aware she is about Curley’s insecurity, which causes her to converse with the other men in secret. Curley expects his wife to do as he tells her at all times, and expects her to isolate herself from everyone else and to only talk to him. In addition, Curley’s wife also adds after discovering where Curley had gone too â€Å"Think I don’t know where they all went? Even Curley?† (77) Curley’s wife despises the requirements and demands her husband has over her, fully knowing that Curley is unfaithful to her. Using this against her husband, Curley’s wife does the exact opposite of what he tells demands of her, and does as she wants whenever Curley isn’t around, and tries to have the guys understand that all she needs is a friend. Curley’s wife, being a woman, is expected to obey a man at all times, but since she is a free-spirited woman, she has hopes and dreams just like everyone else that she had to give up to spend the rest of her miserable life being isolated. Candy, the old swamper, is a lonely character because he is different from  everyone else and doesn’t really have anybody to call â€Å"friend†. For example, Candy tells George, â€Å"I’d make a will an’ leave my share to you guys in case I kick off, ‘cause I ain’t got no relatives nor nothing.† (59) Candy clearly says in this statement that he is desperate to not spend the rest of his life alone. He was willing to give George and Lennie his life savings to be a part of their American Dream, and clings to the idea of having the freedom to take up or set aside work as he chooses. In addition, Candy continues to persuade George, â€Å"When they can me here I wisht somebody’d shoot me. But they won’t do nothing like that. I won’t have no place to go, an’ I can’t get no more jobs.† (60) Candy compares himself to his old dog that was shot because he was no longer useful and the guys at the ranch didn’t want him to suffer anymore. He knows that he will get fired from his job soon, because he as well is getting very old and useless, and wished that once he does get fired, one of the men on the ranch will shoot him to put him out of his misery, because he will have no one left to spend his life with. Candy is a hard worker, however, he fears that he will be alone for the rest of his life and tries to do everything in his power to avoid that worrying obstacle. Crooks is a lively, sharp-witted, African American who takes his name from his crooked back. Like most of the characters in the story, he admits that he is awfully lonely. When Lennie visits him in his room, his reaction certainly reveals this fact. â€Å"’Why ain’t you wanted?’ Lennie asked. ‘Cause I’m black.’† (68) At first when Lennie visited Crooks, he turns Lennie away, hoping to prove a point that if he, as a black man, is not allowed in white men’s houses, then whites are not allowed in his. However, his desire for company ultimately wins out and he invites Lennie to sit with him. Like Curley’s wife, Crooks is a disempowered character who turns his vulnerability into a weapon to attack those who are even weaker. Crooks adds, â€Å"A guy sets alone here at night, maybe readin’ books or thinkin’ or stuff like that. Sometimes he gets thinkin’, an’ he got nothin’ to tell him what’s so an’ ain’t so. Maybe if he sees somethin’, he don’t know whether it’s right or not. He can turn to some other guy and ast him if he sees it too.† (73) Crooks as a black and handicapped man, is forced to live on the periphery of ranch life. He is not even allowed to enter the white men’s  bunkhouse, or join them in a game of cards. His resentment typically comes out through his bitter harsh intellect, but in this passage he displays a desolate, touching vulnerability. Crooks desire for a friend by whom to â€Å"measure† things echoes George’s earlier description of the life of a migrant worker. These characters each crave the reassurance of a friend at one time or another and are all rendered helpless by their isolation, and yet, even at their weakest, they seek to destroy those who are even weaker than they are. Because of this strong feeling of loneliness, it isn’t surprising that the promise of a farm of their own life filled with strong bonds holds such allure.

Pow 12 Imp 1

1. To find my conclusions I had to think about each part of the problem. When you know that one thing means you go on to the next part. When you figure out what that means you have to see how the two statements are related. If they are related then you can deduce a conclusion that makes sense. 2. Here are my conclusions for the 6 problems on page 7. 1. a. No medicine is nice b. Senna is a medicine Here I deduced that Senna is not a nice medicine. I think this because the first statement says that â€Å"no medicine is nice. † That tells me that all medicines are not nice. The second statement says â€Å"Senna is a medicine†. That statement is straight forward. When you put them together you can decide that Senna is a medicine and medicines are not nice. So Senna is not nice. 2. a. All shillings are round b. These coins are round Here I decided that no now conclusions can be drawn. The first statement says â€Å"All shillings are round. † That statement is clear. The second statement says â€Å"These coins are round. † This tells you the coin they have are round. When you put these statements together you can see some flaws. They say these coins but you don’t know if any of these coins are shillings. They can be other coins that are round. So you cannot deduce anything. These coins are 3. a. Some pigs are wild b. All pigs are fat Here I decided that there are no conclusions that can be made. The first statement tells you that some pigs are wild and the second tells you that all pigs are fat. But when you put these statements together you get wild pigs are fat but you already know that because the second statement says that all pigs are fat. Thus you cannot deduce anything. . a. Prejudiced persons are untrustworthy b. Some unprejudiced persons are disliked Here there are no conclusions that can be made. These statements are just statements are just statements and you cannot deduce anything from them. If you combine these statements you get prejudice persons are untrustworthy and some are disliked. 5. a. Babies are illogical b. Nobody who is despised can manage a crocodile c. Illogical persons are d espised Here I deduce that Babies cannot manage a crocodile. The first statement says that Babies are illogical. The third statement says that illogical persons are despised. When you put those statement together you get babies are despised. Then you have to look at the second statement. Nobody who is despised can manage a crocodile. So when you put those statements together you get babies cannot manage a crocodile. 6. a. No birds, except ostriches, are 9 feet tall b. There are no birds in the aviary that belong to anyone but me c. No ostrich lives on mince pies d. I have no birds less that 9 feet tall. Here I deduced that the birds in the aviary are ostriches and they do not eat mince pies.. To deduce this I combined the third and fourth statements. Together it says that no birds less than 9 feet tall are in the aviary. Then when you combine that statement with the fourth statement you deduce that the birds in the aviary are ostriches. And when you conclude the third statement you get a final statement that says the birds in the aviary are ostriches and they do not eat mince pies. Part Two Valid Conclusion: People with hats are untrustworthy Untrustworthy people are dangerous. Invalid Conclusion: Some Golden Retrievers are gold These dogs are gold 3. This POW has to do with mathematics because it is all about logic. In math without logic you would less successful then if you do have logic. If something does not seem right to you or is confusing you are using logic to realize that something is wrong and will use it to solve it. Without logic you wouldn’t know when something is right or wrong. 4. This POW was fairly simple. But some of the problems required you to think more than others. But if you think it out in steps you will be able to solve them easily. I believe that I did well and thought out each problem as well as I can.

The Ethics Of Amateurism And College Athletes - 1645 Words

Salaries, wages, and compensations have always been major and generally controversial topics in democratic America. And, with the rising popularity of college athletics, particularly football, compensation (or lack thereof) for college athletes has recently been a hot topic in American sports. While some of the debate stems from the similarity between responsibilities college athletes have to their programs and those of professionals, most of the issue involves the principles of amateurism. Recent â€Å"scandals† involving college athletes such as Terrelle Pryor, Johnny Manziel, and Todd Gurley have raised questions about the ethics of amateurism, particularly with regard to the NCAA organization. The issue is found in a very gray area, where there is most likely no definitive one-size-fits-all solution, but the resolution of this issue is one that will change and shape the future of college athletics across the national landscape. For as long as second-level institutions have sponsored sports teams to represent their universities, there have been regulations (both official and unofficial) on the athletes, including their safety and benefits. This led to the formation of the NCAA in 1906. The NCAA s formation in the beginning was to preserve the sport itself in a time when the sport was perceived as too dangerous to be played. United States President Theodore Roosevelt actually inadvertently set the NCAA in motion when he convened thirteen football representatives (Treadway,Show MoreRelatedSports : Pay For Play?2343 Words   |  10 PagesAmateurism in College Sports: Pay for Play? Dating back to ancient Greek culture, humans have always enjoyed partaking and watching athletic events. People would travel from all over the globe to see some of these sporting events. The same holds true today, with people from all over the world travelling to play and watch both amateur and professional sports. 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